155 lines
5.6 KiB
Python
155 lines
5.6 KiB
Python
import random
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import datetime
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import re
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class CardGenerator:
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def __init__(self):
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self.current_year = datetime.datetime.now().year
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def luhn_checksum(self, card_number_str):
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"""计算 Luhn 校验和"""
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digits = [int(d) for d in card_number_str]
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checksum = 0
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is_second = False
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for digit in reversed(digits):
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if is_second:
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digit *= 2
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if digit > 9:
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digit -= 9
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checksum += digit
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is_second = not is_second
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return checksum
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def calculate_check_digit(self, card_number_without_check):
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"""计算最后一位校验位"""
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temp_number = card_number_without_check + "0"
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checksum = self.luhn_checksum(temp_number)
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if checksum % 10 == 0:
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return "0"
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else:
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return str(10 - (checksum % 10))
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def generate_card_number(self, pattern):
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"""
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核心生成逻辑：支持任意位置的 'x'
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"""
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# 1. 确定卡号长度标准 (Amex 15位，其他 16位)
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# 如果 pattern 已经很长，就用 pattern 的长度，否则根据卡头判断
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target_len = 16
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if pattern.startswith(('34', '37')):
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target_len = 15
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# 2. 补全 pattern 到目标长度 (减去最后一位校验位)
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# 如果输入的 pattern 比如是 "547958" (长度6)，需要补 x 到 15位 (留一位给校验)
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# 如果输入已经包含了 x 且长度足够，则保留原样
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working_pattern = pattern.lower()
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# 移除可能存在的非数字/x字符
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working_pattern = re.sub(r'[^0-9x]', '', working_pattern)
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# 自动填充 x
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if len(working_pattern) < target_len:
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working_pattern += 'x' * (target_len - len(working_pattern))
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# 截断到 倒数第二位 (最后一位是校验位)
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# 注意：如果用户输入了完整的 16位 pattern 且最后一位不是 x，我们会覆盖它，
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# 因为 Luhn 算法要求最后一位必须是计算出来的。
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# 除非用户就是想校验？但在生成逻辑里，我们通常假设最后一位是计算的。
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base_pattern = working_pattern[:target_len-1]
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generated_prefix = ""
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for char in base_pattern:
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if char == 'x':
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generated_prefix += str(random.randint(0, 9))
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else:
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generated_prefix += char
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# 计算校验位
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check_digit = self.calculate_check_digit(generated_prefix)
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return generated_prefix + check_digit
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def parse_date_cvv(self, card_num, m_req, y_req, c_req):
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"""
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处理日期和CVV的占位符逻辑
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"""
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# --- Month ---
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if m_req in ['(m)', 'rnd', '', None]:
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month = str(random.randint(1, 12)).zfill(2)
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else:
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month = m_req.strip() # 使用用户指定的静态值，如 '05'
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# --- Year ---
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if y_req in ['(y)', 'rnd', '', None]:
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year = str(self.current_year + random.randint(2, 5))
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else:
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year = y_req.strip() # 使用用户指定的静态值，如 '2023' 或 '23'
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# --- CVV ---
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if c_req in ['(cvv)', 'rnd', '', None]:
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if card_num.startswith(('34', '37')):
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cvv = str(random.randint(1102, 9999))
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else:
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cvv = str(random.randint(112, 999))
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else:
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cvv = c_req.strip()
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return month, year, cvv
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def process_line(self, raw_input, count=1):
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"""
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智能解析输入字符串并生成
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支持格式：
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- BIN only: 547958
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- Pattern: 460723xxxxxxxxxx
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- Complex: 5319719xxx5xxx87
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- Full: 434256|11|2022|212
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- Templates: 434256|(m)|(y)|(cvv)
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"""
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# 默认值
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parts = raw_input.split('|')
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# 提取各个部分，没有的就设为 None，交给 parse_date_cvv 处理默认逻辑
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pattern_part = parts[0] if len(parts) > 0 else ""
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month_part = parts[1] if len(parts) > 1 else None
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year_part = parts[2] if len(parts) > 2 else None
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cvv_part = parts[3] if len(parts) > 3 else None
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results = []
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for _ in range(count):
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# 1. 生成卡号
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card_num = self.generate_card_number(pattern_part)
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# 2. 处理附属信息
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m, y, c = self.parse_date_cvv(card_num, month_part, year_part, cvv_part)
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results.append(f"{card_num}|{m}|{y}|{c}")
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return results
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# --- 测试与演示 ---
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if __name__ == "__main__":
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gen = CardGenerator()
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# 你列出的所有测试用例
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test_cases = [
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"547958", # 仅 BIN
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"460723xxxxxxxxxx", # 带图案
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"5319719xxx5xxx87", # 专业用户 (混合 pattern)
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"434256|11|2022|212", # 你自己的固定模式
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"559917|11|2022|(cvv)", # 随机 CVV
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"434256|(m)|(y)|(cvv)", # 全随机占位符
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"434256240669|(m)|(y)|(cvv)", # 短卡号 (没有最后4位) -> 会自动补全
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"53673712123xxxxx|05|2023|", # 指定长年份
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"53673712123xxxxx|05|23|" # 指定短年份
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]
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print(f"{'INPUT FORMAT':<35} | {'GENERATED OUTPUT'}")
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print("-" * 80)
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for case in test_cases:
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# 每个案例生成 1 条作为演示
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output = gen.process_line(case, count=1)[0]
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print(f"{case:<35} -> {output}")
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