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@@ -233,6 +233,55 @@ def log_url_change(page, old_url: str, action: str = None):
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log.warning(f"记录URL变化失败: {e}")
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def acquire_lock_with_keepalive(lock, page, timeout: float = 120, check_interval: float = 2.0) -> bool:
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"""获取锁的同时保持浏览器活跃,防止等待期间浏览器连接断开
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在并发模式下,多个 Worker 可能需要等待授权回调锁。
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如果等待时间过长 (>15-30秒),浏览器连接可能会因为空闲而断开。
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此函数通过定期访问页面来保持浏览器活跃。
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Args:
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lock: threading.Lock 对象
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page: 浏览器页面对象
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timeout: 最大等待时间 (秒)
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check_interval: 检查间隔 (秒)
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Returns:
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bool: 是否成功获取锁
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"""
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import threading
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start_time = time.time()
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acquired = False
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while time.time() - start_time < timeout:
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# 尝试非阻塞获取锁
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acquired = lock.acquire(blocking=False)
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if acquired:
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return True
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# 未获取到锁,保持浏览器活跃
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try:
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# 访问页面属性以保持连接活跃
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_ = page.url
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# 可选:执行一个轻量级操作
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try:
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page.run_js("1+1") # 执行简单的 JavaScript 保持活跃
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except Exception:
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pass
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except Exception as e:
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# 浏览器连接可能已断开
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log.warning(f"保持浏览器活跃时出错: {e}")
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return False
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# 等待一小段时间后重试
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time.sleep(check_interval)
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# 超时,尝试最后一次阻塞获取 (短暂)
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acquired = lock.acquire(blocking=True, timeout=0.1)
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return acquired
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def cleanup_chrome_processes():
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"""清理残留的 Chrome 进程 (跨平台支持)"""
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try:
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@@ -2154,11 +2203,16 @@ def register_and_authorize(email: str, password: str, use_api_register: bool = T
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time.sleep(0.5)
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# ========== 授权流程 - CPA/S2A 需要串行执行 (避免回调端口冲突) ==========
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# 在调用授权函数之前获取锁,确保浏览器不会在等待锁时空闲断开
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# 使用 keepalive 获取锁,防止等待期间浏览器连接断开
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lock_acquired = False
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if auth_lock:
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log.step("等待授权回调锁...")
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auth_lock.acquire()
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log.step("获取授权回调锁,开始授权...")
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lock_acquired = acquire_lock_with_keepalive(auth_lock, ctx.page, timeout=180, check_interval=2.0)
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if lock_acquired:
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log.step("获取授权回调锁,开始授权...")
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else:
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log.error("获取授权回调锁超时或浏览器连接断开")
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continue # 重试
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try:
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# 根据配置选择授权方式
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@@ -2175,7 +2229,7 @@ def register_and_authorize(email: str, password: str, use_api_register: bool = T
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codex_data = perform_codex_authorization(ctx.page, email, password)
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return True, codex_data
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finally:
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if auth_lock:
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if auth_lock and lock_acquired:
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log.step("释放授权回调锁")
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auth_lock.release()
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@@ -2212,10 +2266,16 @@ def authorize_only(email: str, password: str) -> tuple[bool, dict]:
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for attempt in ctx.attempts():
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try:
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# ========== 授权流程 - CPA/S2A 需要串行执行 (避免回调端口冲突) ==========
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# 使用 keepalive 获取锁,防止等待期间浏览器连接断开
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lock_acquired = False
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if auth_lock:
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log.step("等待授权回调锁...")
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auth_lock.acquire()
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log.step("获取授权回调锁,开始授权...")
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lock_acquired = acquire_lock_with_keepalive(auth_lock, ctx.page, timeout=180, check_interval=2.0)
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if lock_acquired:
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log.step("获取授权回调锁,开始授权...")
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else:
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log.error("获取授权回调锁超时或浏览器连接断开")
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continue # 重试
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try:
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# 根据配置选择授权方式
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@@ -2252,7 +2312,7 @@ def authorize_only(email: str, password: str) -> tuple[bool, dict]:
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continue
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return False, None
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finally:
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if auth_lock:
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if auth_lock and lock_acquired:
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log.step("释放授权回调锁")
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auth_lock.release()
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